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Eroare Undefined offset

https://marplo.net/forum/viewtopic.php?f=31&t=1447

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Eroare Undefined offset

Scris: Lun Ian 21, 2013
de alexinio3d
Salutare...
1. Cum as putea sa scap de eroarea aceasta ? :

Cod: Selectaţi tot

Notice: Undefined offset: 0 in C:\xampp\htdocs\magazin\template\header.php on line 38

Notice: Undefined offset: 6 in C:\xampp\htdocs\magazin\template\header.php on line 38

Notice: Undefined offset: 7 in C:\xampp\htdocs\magazin\template\header.php on line 38
Codu mi urmatorul :

Cod: Selectaţi tot

<?php
//------------------------------------------------------------------------------------------------------------+
  header("Content-Type:text/html; charset=utf-8");
//------------------------------------------------------------------------------------------------------------+
//Conectare MySQL-----
require ('./config.php');
//--------------------
?>
<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.1//EN' 'http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd'>
<html>
<head>
<title><?php echo $titlu; ?></title>
<link href="./css/bootstrap.css" rel="stylesheet" media="screen">
<script src="./js/jquery-latest.js"></script>
<script src="./js/bootstrap.js"></script>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link href="assets/css/bootstrap-responsive.css" rel="stylesheet">
</head>
<body>
<!-- Meniu sus -->
<div class="navbar">
    <div class="navbar-inner">
        <a class="brand" href="."><?php echo $titlu; ?></a>
        <ul class="nav">
    <li><a href=".">Home</a></li>
<?php

                $result = mysql_query('select * from store_categories');
                $tree = array();
                while(false !== ($row=mysql_fetch_assoc($result))) {
                    $tree[$row['cat_primary']][$row['id']] = $row['cat_title'];
                }
                $out = "";
                foreach( array_keys($tree) as $cat_primary)
                {
                    $out .= "
                    <li class='dropdown'>
                        <a id='drop_$cat_primary' href='#' role='button' class='dropdown-toggle' data-toggle='dropdown'>".$tree[0][$cat_primary]."</a>
                        <ul class='dropdown-menu' role='menu' aria-labelledby='drop_$cat_primary'>";
                    foreach ( array_keys($tree[$cat_primary]) as $cat )
                        {
                            $out .= "<li class=\"dropdown-submenu\"><a tabindex=\"-1\" href='./seestore.php?cat_id=$cat'>".$tree[$cat_primary][$cat]."</a><ul class='dropdown-menu' role='menu' aria-labelledby='drop_$cat_primary'>";
                        foreach ( array_keys($tree[$cat_primary]) as $cat )
                        {
                            $out .= "<li><a tabindex=\"-1\" href='./seestore.php?cat_id=$cat'>".$tree[$cat_primary][$cat]."</a></li>";
                        }
                            $out .= "
                        </ul>
                    </li>";
                        }
                        $out .= "
                        </ul>
                    </li>";
                }
                echo $out;
?>
<li><a href=".">Contact</a></li>
</ul>
</div>
</div>
<!-- Meniu sus -->

Eroare Undefined offset

Scris: Mar Ian 22, 2013
de MarPlo
Salut
Eroarea indica faptul ca se acceseaza elemente de array care nu exista.
Explicatie si solutie generala la aceasta eroare gasesti aici:
https://coursesweb.net/php-mysql/common- ... #perr14_13

Nu stiu exact solutia la tine, dar incearca sa inlocuiesti la linia 38 codul:

Cod: Selectaţi tot

$tree[0][$cat_primary]
Cu acesta:

Cod: Selectaţi tot

(isset($tree[0][$cat_primary]) ? $tree[0][$cat_primary] : '')
 
Cred ca nu va mai da acea eroare, dar daca nu rezulta meniul cum vrei, trebuie refacut o parte din cod (de catre cine-l foloseste).

Eroare Undefined offset

Scris: Mie Ian 23, 2013
de alexinio3d
Si mai am inca 2 probleme la meniu:
1. De ce numi apare si categoriia care nu are subcategorii?? :-s
2. Cum pot sa fac sami arete subcategoriile la subcategorii :), pentru ca mie imi arata asa, link imagine:
imageshack.us/photo/my-images/267/61337792.png/
Adica vreau sa zic ca in loc sa arate subcategoriile subcategoriei leagane el imi arata inca o data subcategoriile, categoriei Mobilier extern
Scriptul mi asa:

Cod: Selectaţi tot

<?php
//------------------------------------------------------------------------------------------------------------+
  header("Content-Type:text/html; charset=utf-8");
//------------------------------------------------------------------------------------------------------------+
//Conectare MySQL-----
require ('./config.php');
//--------------------
?>
<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.1//EN' 'http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd'>
<html>
<head>
<title><?php echo $titlu; ?></title>
<link href="./css/bootstrap.css" rel="stylesheet" media="screen">
<script src="./js/jquery-latest.js"></script>
<script src="./js/bootstrap.js"></script>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link href="assets/css/bootstrap-responsive.css" rel="stylesheet">
</head>
<body>
<!-- Inceput - Meniu sus -->
<div class="navbar">
    <div class="navbar-inner">
        <a class="brand" href="."><?php echo $titlu; ?></a>
        <ul class="nav">
    <li><a href=".">Home</a></li>
<?php

                $result = mysql_query('select * from store_categories');
                $tree = array();
                while(false !== ($row=mysql_fetch_assoc($result))) {
                    $tree[$row['cat_primary']][$row['id']] = $row['cat_title'];
                }
                $out = "";
                foreach( array_keys($tree) as $cat_primary)
                {
                if(isset($tree[0][$cat_primary]) ? $tree[0][$cat_primary] : '') {
                    $out .= "
                    <li class='dropdown'>
                        <a id='drop_$cat_primary' href='#' role='button' class='dropdown-toggle' data-toggle='dropdown'>". $tree[0][$cat_primary] ."</a><ul class='dropdown-menu' role='menu' aria-labelledby='drop_$cat_primary'>";
                    foreach ( array_keys($tree[$cat_primary]) as $cat )
                        {
                            $out .= "<li class=\"dropdown-submenu\"><a tabindex=\"-1\" href='./seestore.php?cat_id=$cat'>".$tree[$cat_primary][$cat]."</a><ul class='dropdown-menu' role='menu' aria-labelledby='drop_$cat_primary'>";
                        foreach ( array_keys($tree[$cat_primary]) as $cat )
                        {
                            $out .= "<li><a tabindex=\"-1\" href='./seestore.php?cat_id=$cat'>".$tree[$cat_primary][$cat]."</a></li>";
                        }
                            $out .= "
                        </ul>
                    </li>";
                        }
                        $out .= "
                        </ul>
                    </li>";
                }
                }
                echo $out;
?>
<li><a href=".">Contact</a></li>
</ul>
</div>
</div>
<!-- Sfarsit - Meniu sus -->
<!-- Inceput - Container -->
<div class="container-table">

Eroare Undefined offset

Scris: Mie Ian 23, 2013
de MarPlo
Asta e traba cu scripturi copiate. Cel mai bine sa inveti sa faci propriul cod, sau sa te pricepi sa modifici.
Nu stiu de ce nu face meniul cum vrei, incearca sa intrebi acolo de unde ai codul.
Ora este UTC+03:00 UTC+3
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