Forum

Scris: **Sâm Feb 11, 2017**

Salut,
In folderul "/includes/" am creat alte foldere cu diferite denumiri (xxx, yyy, zzz)

if(stristr($_SERVER['REQUEST_URI'], '/includes/') !== false){
  echo 'Adresa URL contine /includes/';
}

Codului de mai sus cum ii pot pune conditia ca dupa '/includes/' indiferent de denumirea ce urmeaza sa se execute if-ul?
Doresc sa fac acest lucru pentru a nu fi nevoit sa fac de fiecare data elseif

Cod: Selectaţi tot

if(stristr($_SERVER['REQUEST_URI'], '/includes/') !== false){
  echo 'Adresa URL contine /includes/';
}
elseif(stristr($_SERVER['REQUEST_URI'], '/includes/xxx/') !== false){
  echo 'Adresa URL contine /includes/xxx';
}
elseif(stristr($_SERVER['REQUEST_URI'], '/includes/yyy/') !== false){
  echo 'Adresa URL contine /includes/yyy';
}
.....

Multumesc!

Scris: **Sâm Feb 11, 2017**

Salut,
Incearca acest cod:

Cod: Selectaţi tot

$chk_dir ='/includes/';  //base directory to check if it is in URL
if(preg_match('#'. $chk_dir .'(.*?)[/]*$#i', $_SERVER['REQUEST_URI'], $mt)){
  $mt[0] = preg_replace('#/[^/]*$#i', '', $mt[0]); //keep only directory path, without file name
  echo 'Adresa URL contine: '. $mt[0];
}
else {
  echo 'Adresa URL Nu contine: '. $chk_dir;
}

Scris: **Dum Feb 12, 2017**

functioneaza, multumesc mult de ajutor!

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